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0.36-x^2=0
We add all the numbers together, and all the variables
-1x^2+0.36=0
a = -1; b = 0; c = +0.36;
Δ = b2-4ac
Δ = 02-4·(-1)·0.36
Δ = 1.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.44}}{2*-1}=\frac{0-\sqrt{1.44}}{-2} =-\frac{\sqrt{}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.44}}{2*-1}=\frac{0+\sqrt{1.44}}{-2} =\frac{\sqrt{}}{-2} $
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